Type-1
Logic based on –Arithmetic progression
We all are familiar with the term of arithmetic Progression .let us take recap of this concept .
If a series is written like this way –
a a + d a + 2d a + 3d a + 4d a + 5d ----------------- a +(n-1) d
first term = a , common difference(d) = next term – previous term , last term = a +( n-1)d
Example - 4 8 12 16 20 ? ?
In this sequence we can easily see when we go from left hand side to right hand side continuously then there is a gape of 4 which is nothing but common difference so .after 20 there will gape of 4 so term will be = 20 + 4 = 24 and 24 +4 = 28
2nd example - 1.5 3 4.5 6 7.5 ?
In first look always try to solve questions with this common difference logic if it will not work then we will switch on another logic but here , it is working
Common difference in series = 3- 1.5 = 4.5-3 = 6-4.5 = 7.5-6 = 1.5 = same
So, when we go from left to right in series then for getting next term we will only add 1.5 to its previous term so ,
7.5 + 1.5 = 9
Tips –In first look try to use this logic when you see that series is increasing/ decreasing slowly .
TYPE -2
LOGIC BASED ON - INCREASING SERIES / DECREASING SERIES WITH
SOME FIXED PATTERN
We can best understand with some good examples –
Increasing series -2 5 9 14 20 27 ?
Step-1 3 4 5 6 7 ----- take common diff.
Step 2 1 1 1 1 1 7+1=8 so, number=27 +8=35
Note – either we can move from left hand side to right with addition or from right to left with subtraction .it is up to you but better to move from left to right .
Decreasing series-
3 3 3 3 88-3 = 85
Common diff.= 3
TYPE -3 MULTIPLICATION SERIES
It is one of popular pattern especially asked in banking examinations of any standard i.e., PO level or clerical level. In these days these type of questions have been framed by Tata consultancy service, the most prominent exam taking agency in India so, once you learn here then you will able to crack this type of series easily in any of the competitive exams.
we will understand this by taking one basic example based on multiplication series. multiplications is done for increasing the series.
100 100 150 300 750 ? ?
Sol- In first view you see there is no changing in first two initial numbers so, you should think how we can easily bring the second number from the first beginning number , it is simply by multiplying by 1. Similarly think how you will bring third number from second number you will be get multiplying by 1.5.
second number= 100= 100 * 1
third number(150)= 100 * 1.5
fourth number (300)= 150 * 2
we are seeing number(multiplication number is increasing by 0.5)
fifth number (750) = 300 * 2.5
sixth number (?) = 750 * 3 = 2250
seventh number (?) = 2250 * 3.5=7875
There are some popular questions is being provided here which comes frequently in all competitive exams.
Q1. 8 12 24 60 ?
Sol- 12 = 8 * 1.5
Note- At first think how second number we can bring from first number so, 12 can get from 8 by multiplying with 12/8 i.e.,3/2=1.5 .
24 = 12 *2
60= 24 * 2.5
?= 60 * 3= 180
Q2. 1.5 1.5 2.25 4.50 11.25 ?
Sol- 1.5 = 1.5 * 1
2.25 = 1.5 * 1.5
4.50 = 2.25 * 2
11.25 = 4.50 * 2.5
? = 11.25 * 3= 33.75.
Q3. 150 150 300 900 3600 ?
Sol- 150 = 150 *1
300 = 150 * 2
900 = 300 *3
3600 = 900 * 4
? = 3600 * 5 = 180000
Q4. 100 50 50 75 150 ?
Sol- 50 = 100 * 1/2
50 = 50 * 1
75 = 50 * 1.5
150 = 75 * 2
? = 150 * 2.5 = 375
Q5. 420 210 140 105 84 ?
Sol- 210 = 420 * 1/2
140 = 210 * 2/3
105 = 140 * 3/4
84= 105 * 4/5
? = 84 * 5/6 = 70
TYPE- 4
Square Series(Square of natural number N^2)- As from its name, it is clear this concept is based upon squaring of a number. To solve quickly , it is very necessary to memorize table from 11 to 30.
Ex- 121 144 169 196 ? ?
Sol- 11 ^2 12^2 13 ^2 14 ^2 15^2 16^2
so, ? = 225 and another ? = 256
Table- Square table from 11 to 30
11 |
121 |
12 |
144 |
13 |
169 |
14 |
196 |
15 |
225 |
16 |
256 |
17 |
289 |
18 |
324 |
19 |
361 |
20 |
400 |
21 |
441 |
22 |
484 |
23 |
529 |
24 |
576 |
25 |
625 |
26 |
676 |
27 |
729 |
28 |
784 |
29 |
841 |
30 |
900 |
LOGIC BASED ON -
( NATURAL NO.)² + 1
TYPE-6
LOGIC BASED ON- (NATURAL NO.)^2 - 1
EX1. 0 3 8 15 24 ?
Sol- 0= 1^2-1 , 3 = 2^2-1 , 8 = 3^2 -1, 15= 4^2 -1 , 24= 5 ^2 -1 similarly ,
next missing number will be = 6^2 -1 = 35
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