Mensuration RRB NTPC Quiz Part 2

 In these days the world's most toughest  competitive exam is going to conduct in next upcoming month in which more than one crore aspirants have  been appeared, First part has already passed and now second cbt part2 is left to be conducted.

Here the most important questions collections from mensuration topic has been given here which will be helpful for railway cbt part2 as well as rrb group d exam.


Q1. The parallel sides of a trapezium are in the ratio of 2:3 and their shortest distance is 12 cm. If the area of trapezium is 480 sq. cm. Find the longer of the parallel sides is of length?/

a. 56 cm

b. 36cm

c.42 cm

d.48 cm

Sol- Area of trapezium = 1/2  * sum of parallel sides * shorter distance/given distance

                                     = 1/2 * (2p + 3p) * 12

                                   = 1/2 * 5p * 12   = 30p 

 or, 480 = 30p      or,  1p = 480/30 = 16cm 

so, longer side of the trapezium = 3p = 3 * 16 = 48cm 

option d correct.


Note- * = multiplication.


Q2. The perimeter of non-square rhombus is 20cm. one of its diagonal is 8cm. Find the area of the rhombus is?

a.28 sq.cm

b. 20 sq.cm

c.22 sq.cm

d. 24  sq.cm

Sol-  Non square rhombus only differs in angles with square rhombus. In sides all sides are equal.

4 * sides of rhombus = 20cm 

or, side= 20/4 = 5 cm 

Hence , option d is correct.

Q3. A street of width 10 meters surrounds from outside a rectangular garden whose measurement is 200m  * 180 m . The area of the path in sq.metre is ?
a.8000
b.7000
c.7500
d.8200

Sol- Here street of width 10metre from outside has been given so, new width of an rectangular filed will be =  200 +10+10 = 220m

and length will be = 180 + 10 + 10 = 200m

New area = 220 * 200 = 44000 sq.metre 

this will area of garden with street.


area of garden without street = 200 * 180 = 36000 sq. metre.

hence, area of path = 44000 - 36000 = 8000 sq. metre

option a is correct.


Q4. Find the area of a rectangular hexagon of side 2root3 cm?

a.18root3

b.12root3

c.36root3

d.27root3


Sol- Area of regular hexagon= 3root3/2 * (side)^2

                                             = 3 root three /2 * 2root3 * 2root 3

                                              = 18 root 3 sq.cm




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